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∠CDB = 3/5 x (180-90)° = 3 x 18° = 54° => ∠CDB = ∠ADB
∠DAB = 5 x 18° = 90°
a.) ∠DCA = 2/5 x (180-90)° = 2 x 18° = 36°
b.) ∠ABD = (180°- (∠DAB+∠ADB))
= (180° - (90°+54°)
= (180° - 144°) = 36°
c.) ∠DCB = d.) ∠DAB = 90°