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H2SO4= 0,025 L ; 0,1 M
molH2SO4= 2,5 x 10^(-3)
molKOH= 5 x 10^(-3)
n=m/Mr
5 x 10^(-3)=m/56
m=280 x 10^(-3)
m= 0,28 gram
persentase= 0,28/0,5 x 100% = 56%