Materi : Bentuk Akar dan Pangkat
A. √3 . √5 = √( 3 × 5 ) = √15
B. 3√7 × 3√2 = ( 3 × 3 )√( 7 × 2 ) = 9√14
C. 2√3 × √24 = 2√( 24 × 3 ) = 2√( 36 × 2 ) = 12√2
D. 6√2 × ⅔√18 = ( 6 × ⅔ )√( 2 × 18 ) = 4√36 = 24
E. 2√3( √2 + √3 ) = 2√6 + 2(3) = 6 + 2√6
F. 3√5( √3 - √2 ) = 3√15 - 3√10
G. ( √2 + √3 )² = (2) + 2√6 + (3) = 5 + 2√6
H. ( √5 + √3 )( √5 - √3 ) = (5) - (3) = 2
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Materi : Bentuk Akar dan Pangkat
A. √3 . √5 = √( 3 × 5 ) = √15
B. 3√7 × 3√2 = ( 3 × 3 )√( 7 × 2 ) = 9√14
C. 2√3 × √24 = 2√( 24 × 3 ) = 2√( 36 × 2 ) = 12√2
D. 6√2 × ⅔√18 = ( 6 × ⅔ )√( 2 × 18 ) = 4√36 = 24
E. 2√3( √2 + √3 ) = 2√6 + 2(3) = 6 + 2√6
F. 3√5( √3 - √2 ) = 3√15 - 3√10
G. ( √2 + √3 )² = (2) + 2√6 + (3) = 5 + 2√6
H. ( √5 + √3 )( √5 - √3 ) = (5) - (3) = 2
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]