Question

Tolong dong jawab no 8

Answer 1

Kf/Kb = 3,6
ΔTf = 0 - (-0,93) = 0,93⁰C


Pada kasus ini, molalitas larutan adalah sama

ΔTf = m . Kf
⇒ m = ΔTf/Kf

ΔTb = m . Kb
⇒ m = ΔTb/kb

Sehingga : 
m₁ = m₂
ΔTf/Kf = ΔTb/Kb
ΔTf . Kb = ΔTb . kf
Kf/Kb = ΔTf/ΔTb
3,6 = 0,93/ΔTb
ΔTb = 0,93/3,6
ΔTb = 0,2583°C

Tb = Tb °+ ΔTb
Tb = 100 + 0,2583
Tb = 100,26⁰C (Jawaban B)