Tolong dong jawab nmr 9 &10 # butuh banget.... Question from @Aulia958

Syubbana No 9)

(2 -1) C = (10   3)
(3 4 ) ( 7   10)

C = 1/11 ( 4 1) (10 3)
   ( -3 2) ( 7 10)

   = 1/11 (47 22)
   (16 11)

   = (47/11 2 )
   (16/11 1 )

n0 10a)
(2 3)(x) = (5)
(3 2)(y) (5)

(x) = 1/-5 (2 -3) (5)
(y) (-3 2) (5)

   = -1/5 (-5)
      (-5)

   = (1)
      (1)

10 b

1/x = a dan 1/y = b

(2 5) (a) = (2)
(3 4) (b) = (5)

(a) = 1/-7 (4 -5)(2)
(b)    (-3 2)(5)

   = 1/-7 (-17)
(4)

   = (17/7)
(-4/7)

1/x = a
1/x = 17/7
17x = 7
x = 7/17

1/y = b
1/y = -4/7
-4y = 7
y = -7/4

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whongaliem 9) $\left[\begin{array}{ccc}2&- 1\\3&4\\\end{array}\right] .C = \left[\begin{array}{ccc}- 10&3\\7&10\\\end{array}\right]$

$\frac{1}{11} \left[\begin{array}{ccc}4&1\\- 3&2\\\end{array}\right] \left[\begin{array}{ccc}2&- 1\\3&4\\\end{array}\right] .C = \frac{1}{11} \left[\begin{array}{ccc}4&1\\- 3&2\\\end{array}\right] \left[\begin{array}{ccc}-10&3\\7&10\\\end{array}\right]$

$C =\frac{1}{11} \left[\begin{array}{ccc}- 33&22\\44&11\\\end{array}\right]$

$C = \left[\begin{array}{ccc}- 3&2\\4&1\\\end{array}\right]$

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Tolong jawab pake cara nmr 21 #butuh banget

Tolong jawab nmr 9, 10

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