Question

Tolong dong bro or sis

Answer 1

Saya bantu 1-4 ya

1.(∛10)ˣ⁺² = 1/100
10¹/³⁽ˣ⁺²⁾ = 10⁻²
1/3 (x + 2) = -2 **dikali 3 supaya 1/3 hilang**
x + 2 = -6
x = -8

2. sudah benar

3. f(x) = 3ˣ
f(a + 2b) = 3⁽ᵃ⁺²ᵇ⁾ atau 3ᵃ . 3²ᵇ
3ᵃ . 3²ᵇ = f(a) . f(2b)

4.(12 + √18)/ √6 **penyebut dan pembilang dikali √6 supaya akar di penyebut hilang**
= √6(12 + √18)/ 6
= [12√6 + √(6 x 18)] / 6
= [12√6 + √(6 x 6 x 3] / 6
= (12√6 + 6√3) / 6
= 2√6 + √3
= 2√3 √2 + √3
= √3(2√2 + 1)