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Materi : Program LinearBahasan : Pertidaksamaan Linear
Jawaban : HP = {x | - 3 < x < 5, x ∈ R}
Langkah - langkah :
2x + 15 > x²
⇔
- x² + 2x + 15 > 0
⇔
x² - 2x - 15 < 0
Faktorisasi :
(x - 5) (x + 3) < 0
x = 5 atau x = - 3
Garis Bilangan dan Intervalnya :
+++ (- 3) ---- (5) +++
Karena diminta x < 0 (negatif), maka :
HP = {x | - 3 < x < 5, x ∈ R}