Question

Tolong djawab, jangan ngasal! ​

Answer 1

f(x) = 1/2(a^x + a^-x) = 1/2(a^x + 1/a^x) = 1/2(a^2x + 1)/a^x)) = (a^2x+1)/(2.a^x)

f(y) = (a^2y + 1)/(2.a^y)

g(x) = 1/2(a^x - a^-x) = 1/2(a^x - 1/a^x) = 1/2(a^2x -1)/(a^x) = (a^2x -1)/(2.a^x)

g(y) = (a^2y -1)/(2.a^y)

berarti :

f(x).f(y) + g(x).g(y) =

(a^2x + 1)/(2.a^x) .(a^2y + 1)/(2.a^y) + (a^2x-1)/(2.a^x) .(a^2y-1)/(2.a^y) =

[(a^(2x+2y) + a^2x + a^2y +1)/(4.a^(x+y)] + [(a^(2x+2y) - a^2x -a^2y + 1)/(4.a^(x+y)] =

[2.a^(2x+2y) + 2) / (4.a^(x+y)] =

2(a^(2x+2y)+1 / (2(2a^(x+y)) =

(a^(2x+2y) + 1)) / (2a^(x+y)) =

2 (1/2.a^(2x+2y) + 1/2)) / 2(a^(x+y)) =

(1/2(a^(2x+2y) + 1)/(a^(x+y)