Jawaban:
Diketahui:
s = 20 cm
f = 12 cm
Ditanyakan: s' dan M = .…?
@Ara1412
jarak bayangan (s')
1/f=1/s+1/s'
1/12=1/20+1/s'
1/s'=1/12–1/20
1/s'=10-6/120
1/s'=4/120
s'=30 cm
perbesaran bayangan (M)
M=S'/S
M=30 cm/20 cm
M=1,5 cm
#Semoga membantu :)
#Pencinta fisika
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Jawaban:
Diketahui:
s = 20 cm
f = 12 cm
Ditanyakan: s' dan M = .…?
@Ara1412
jarak bayangan (s')
1/f=1/s+1/s'
1/12=1/20+1/s'
1/s'=1/12–1/20
1/s'=10-6/120
1/s'=4/120
s'=30 cm
perbesaran bayangan (M)
@Ara1412
M=S'/S
M=30 cm/20 cm
M=1,5 cm
@Ara1412
#Semoga membantu :)
#Pencinta fisika