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x²-2x-4(y²-6y) = 39
x²-2x+1 -4(y²-6y+9) = 39+1-36
(x-1)²-4(y-3)² = 4 --> kdua ruas dibagi 4
(x-1)² - (y-3)² = 1
4 1
hiperbola tsb merupakan hiperbola horisontal
(x-p)² - (y-q)² = 1
a² b²
(x-1)² - (y-3)² = 1
4 1
mempunyai
a² = 4 --> a = 2
b² = 1 --> b = 1
p = 1 dan q = 3
puncak hiperbola
(p+a,q) --> (1+2,3) --> (3,3)
(p-a,q) --> (1-2,3) --> (-1,3)