Question

Tolong dijawab ya , Terima kasih

Answer 1

A) R1, R2, R3 dipararel
1/Rp = 1/R1 + 1/R2 + 1/R3
1/Rp = 1/60 + 1/120 + 1/40
1/Rp = 2+1+3 / 120
1/Rp = 6/120
Rp = 120/6
Rp = 20 Coulomb

B) Arus listrik dalam rangkaian
I = V/R
I = 6/20
I = 0,3 A

C) Arus listrik R1, R2
· R1 :
I = V/R1
I = 6/60
I = 0,1 A
· R2 :
I = V/R2
I = 6/120
I = 0,05 A