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Verified answer
Diketahui:R = jari-jari alas kerucut terpancung = 10 cm
r = jari-jari atap kerucut terpancung = 5 cm
s2 = panjang garis pelukis kerucut terpancung = 12 cm
Ditanya:
Luas selimut kerucut terpancung = ...?
Jawab:
Luas selimut kerucut terpancung
= π . s2 . (R + r)
= π . 12 . (10 + 5)
= π . 12 . 15
= 565,2 cm²