g:x → x²+2
{x|-3<x<3, x€bil.bulat}
g(x) = x²+2
domain = -3,-2,-1,0,1,2,3
g(-3) = -3²+2 = 9+2 = 11
g(-2) = -2²+2 = 4+2 = 6
g(-1) = -1²+2 = 1 + 2 = 3
g(0) = 0²+2 = 0+2 = 2
g(1) = 1²+2 = 1+2 = 3
g(2) = 2²+2 = 4+2 = 6
g(3) = 3²+2 = 9+2 = 11
{-3,11},{-2,6},{-1,3},{0,2},{1,3},{2,6},{3,11}
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Verified answer
g:x → x²+2
{x|-3<x<3, x€bil.bulat}
g(x) = x²+2
domain = -3,-2,-1,0,1,2,3
g(-3) = -3²+2 = 9+2 = 11
g(-2) = -2²+2 = 4+2 = 6
g(-1) = -1²+2 = 1 + 2 = 3
g(0) = 0²+2 = 0+2 = 2
g(1) = 1²+2 = 1+2 = 3
g(2) = 2²+2 = 4+2 = 6
g(3) = 3²+2 = 9+2 = 11
{-3,11},{-2,6},{-1,3},{0,2},{1,3},{2,6},{3,11}