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ket.
n= jumlah bilangan dari suku 1 sampai suku terakhir
a= suku pertama
b=beda dari satu bilangan
1. 1+...+99 =50/2×(2×1+(50-1)×2)
= 25×100
= 2500
2.1+...+100= 100/2×(2.1+(100-1)×1)
= 50×101
= 5050
3.-100+...+50 = 150/2×(2.-100+(150-1)×1)
: = 75×-51
=3825