Question

Tolong dijawab pake caranya

Answer 1

Verified answer

Kelas 8 Matematika
Bab Persamaan Garis

(0, -2) dan (3, 0)

m1 = (y2 - y1)/(x2 - x1)
m1 = (0 + 2)/(3 - 0)
m1 = 2/3

m1 . m2 = -1
2/3 . m2 = -1
m2 = -1 . 3/2
m2 = -3/2

(3, 0)

Persamaan garis k
y - y1 = m (x - x1)
y - 0 = (-3/2) . (x - 3)
2y = -3x + 9
3x + 2y = 9

Answer 2

Verified answer

Misal garis l melalui (3, 0) dan (0,-2)
(y -y1)/(y2 - y1) = (x - x1)/(x2 - x1)
( y -0)/(-2-0) = (x -3)/(0-3)
y/-2 = (x -3)/-3
-3y = -2x +6
y = (-2x +6)/-3
y = 2/3x -2. gradien m1 = 2/3
m1.m2 = -1, ( karena tegak lurus)
2/3.m2 = -1
m2 = -3/2. dan melalui (3,0)
y - 0 = -3/2(x - 3)
y = -3/2x +9/2