Question

Tolong dijawab pake cara, pertanyaan nya kuat arus penghantar p?

Answer 1

1/Rp= 1/R1 + 1/R2 + 1/R3

1/Rp = 1/12 + 1/6 + 1/4

1/Rp= 1/12 + 2/12 + 3/12

1/Rp = 6/12

Rp = 12/6

Rp = 2 Ω

Rtotal = 2 Ω + 2 Ω + 2 Ω

Rtotal = 6 Ω

Kuat arus

I = V / R

I = 12 / 6

I = 2 A

Answer 2

I = V : R total

V = 12 V

R total = (1/12+1/6+1/4)+2+2

= (1/12+2/12+3/12) + 2 + 2

= (6/12) +2 +2

= (12/6) + 2 +2

= 2+2+2

= 6


I = 12 ÷ 6

= 2 A