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1/cos α = x/1
cos α = 1/x
sin α = √( 1 - cos² α)
sin α = √(1 - 1/x²)= √{(x²-1)/x²}= 1/x √(x² -1)
tan α = sin α / cos α --> tan α = (1/x) √(x² -1) / (1/x)
tan α = √(x² -1)
identitas trigonometri
1 + tan²α = sec²α
1 + tan²α = x²
tan²α = x² - 1
tan α = √(x² - 1)
maka nilai dari tan α adalah √(x² - 1)