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Verified answer
3'log 2 = a5'log 3 = b
6'log 75
= ³log 75 / ³log 6
= ³log (3 × 5²) / ³log (2 × 3)
= (³log 3 + 2 . ³log 5) / (³log 3 + ³log 2)
= (1 + 2/b) / (1 + a)
= (b + 2) / b(1 + a)
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Persamaan garis melalui (-2,3) dan sejajar 3x - 2y + 7 = 0 :
3x - 2y = 3(-2) + (-2)(3)
3x - 2y = -6 - 6
3x - 2y = -12 ✓