Question

tolong dijawab dengan penjelasan makasih

Answer 1

Verified answer

3 (1-sin²x-sin²x)+sinx-2 = 0
3 (1-2sin²x) + sinx - 2. = 0
3-6 sin²x +sinx -2 = 0
-6sin²x + sinx + 1 = 0
6 sin²x - sinx - 1 = 0
(3 sin x +1)(2 sin x-1) = 0

3 sin x = -1
sin x = -⅓

2 sin x = 1
sin x = ½

batasan x (-½π ~ ½π)

sin x = -⅓ --> cos x = ⅔√2
sin x = ½ ---> cos x = ½√3