Question

tolong dijawab dengan benar pliss​

Answer 1

Jawaban:

Volume Bola = VB = 20π

[tex]VB = \frac{4}{3} \pi r {}^{3} \\ 20\pi = \frac{4}{3} \pi r {}^{3} \\ 20 = \frac{4}{3} {r}^{3} \\ 60 = 4 {r}^{3} \\ r = \sqrt[3]{ \frac{60}{4} } \\ r = \sqrt[3]{15} [/tex]

[tex]r = 2r = 2( \sqrt[3]{15} ) \: cm[/tex]

[tex]VB = \frac{4}{3} {\pi \: r}^{3} \\ VB = \frac{4}{3} .\pi.(2 \sqrt[3]{15} ) {}^{3} \\ VB = \frac{4}{3} .\pi. {2}^{3} .( \sqrt[3]{15} ) {}^{3} \\ VB = \frac{4}{3} .\pi.8.15 \\ VB = 32\pi.5 \\ VB = 160\pi \: cm {}^{3} [/tex]

Answer 2

Jawaban:

C. 80π

Penjelasan dengan langkah-langkah:

Volume bola baru

= Volume bola lama × 4

= 20π × 4

= 80π

jari-jari × 2 = volume × 4

diameter × 2 = volume × 4