Jawab:
6a. x + 7
6b. 2x + 1
Penjelasan dengan langkah-langkah:
Komposisikan, misalkan lalu ubah variabel nya.
Nomor 6a
[tex]\begin{aligned}(f\circ g)(x)&=x^2+5x+3\\(f(g(x))&=x^2+5x+3\\f(x^2+5x-4)&=x^2+5x-4+7\\f(a)&=a+7\\f(x)&=x+7\end{aligned}[/tex]
Nomor 6b
[tex]\begin{aligned}(f\circ g)(x)&=2x^2-6x+5\\(f(g(x))&=2x^2-6x+5\\f(x^2-3x+2)&=2(x^2-3x+2)+1\\f(a)&=2a+1\\f(x)&=2x+1\end{aligned}[/tex]
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Jawab:
6a. x + 7
6b. 2x + 1
Penjelasan dengan langkah-langkah:
Komposisikan, misalkan lalu ubah variabel nya.
Nomor 6a
[tex]\begin{aligned}(f\circ g)(x)&=x^2+5x+3\\(f(g(x))&=x^2+5x+3\\f(x^2+5x-4)&=x^2+5x-4+7\\f(a)&=a+7\\f(x)&=x+7\end{aligned}[/tex]
Nomor 6b
[tex]\begin{aligned}(f\circ g)(x)&=2x^2-6x+5\\(f(g(x))&=2x^2-6x+5\\f(x^2-3x+2)&=2(x^2-3x+2)+1\\f(a)&=2a+1\\f(x)&=2x+1\end{aligned}[/tex]