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Answer 1

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LogaRitMa
ᵃlog b = c, syarat numerik  b > 0

13.
a = 0,33..
10a = 3,3
9a = 3
a = 1/3 = 3⁻¹
.
b = √{90 - √(90...
b² = 90 - √(90..
b² = 90 - b
b² + b - 90 = 0
(b + 10)(b -9) = 0
b = -10  atau b = 9 
b > 0 
b = 9 = 3²
.
nilai ᵃlog b = ³^⁻¹ log 3² 
⁸log b = (²/₋₁) (³log 3)
⁸log b = -2 (1)
ᵃlog b = - 2
..
14.
ᵃlog b. ᵇlog a= 1

(²log 3/2 + 1)(³log 2/3+1) =
= (²log 3 - ²log 2  + 1)(³log2 - ³log 3 +1)
= (²log 3 - 1 + 1)(³log 2 - 1 + 1)
= (²log 3)(³log 2)
= ²log 2
= 1
..
20.
ᵃlog (bc) =ᵃlog b +ᵃlog c

²log² x - 3. ²l;og x  -10 = 0
a=1 , b = - 3 , c = -10
akar akarnya ²log x₁ atau ²log x₂
²log x₁ + ²log x ₂ = -b/a = - (-3)/1
²log (x₁. x₂) = 3
x₁.x₂ = 2³
x₁.x₂ = 8
..
(21)
sama cara dengan (20)
"silahkan mencoba"