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x³(2-x²) ≤ 0
pembuat nol:
x = 0
2-x² = 0
x² = 2
x = √2 atau x = -√2
uji tiap daerah, maka didapat:
++++ - - - - - +++++ - - - - -
-√2 0 √2
karena tanda ≤ maka penyelesaian yg -
selang: {x | -√2 ≤ x ≤ 0 atau x ≥ √2}
semoga membantu :)