Question

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Answer 1

Verified answer

4log9 = 1/x
2²log3² = 1/x
(2/2).2log3 = 1/x
2log3 = 1/x

27log8√2
→ 3³log(2³.2^½)
3³log(2^7/2)
((7/2)/3)3log2
(7/6)(1/2log3)
(7/6)(1/(1/x))
(7/6)x = 7x/6 <b>

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