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= 2log x / (2log 2 - 2log x^2)
= 2 log x / 2log (2/x^2)
= (2/x^2)log x
f(2/x) = (2/(2/x)^2) log (2/x)
= (2/4/x^2) log 2/x
= (x^2/2) log 2/x
= (2/x^2)^-1log 2/x
= -1. (2/x^2log2/x)
f(x) + f(2/x) = (2/x^2)log x + ( - (2/x^2log2/x)
= (2/x^2) log (x / 2/x)
= (2/x^2) log (x^2/2)
= -1 (2/x^2)log 2/x^2
= -1 . 1
= -1
Jawaban C