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<==> f(2) = (2+a)+3 = 1
5+a = 1
a = -4
a. f(x) = (x-4)+3 = x-1
b. f(-1) = -1-1 = -2
c. f(-2)+f(-1) = -3-2 = -5
d. f(2x-5) = 2x-5-1 = 2x-6 = 2(x-3)