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diketahui
m beras= 200 kg
m truk+ beras= 450 kg
a= 10m/s²
dtanya= a jika massa beras diturunkan?
jawab=
Ftruk+ beras= mtotal× a= 450×10= 4500 N
a truk saja= F/m truk= 4500/(450-200)
a= 4500/250
a= 18 m/s² (B)
6.
diket= F= 350 N
s= 50m
ditanya= W?
jawab
W= f×s
W= 350×50=17500 Joule (D)
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