Question

Tolong dibantu ya kakak tentang logaritma prnya buat besok
Pakek caranya
Kalo bener & dijawab semua aku kasih yang terbaik deh

Answer 1

Verified answer

A)
²log x + ²log (x - 2) = 3
²log [x(x - 2)] = ²log2³
²log [x(x - 2)] = ²log8

x(x - 2) = 8
x² - 2x - 8 = 0
(x + 2)(x - 4) = 0

x + 2 = 0
x = -2 (tidak memenuhi)

x - 4 = 0
x = 4 (memenuhi)

HP = {4}

b)
log(x - 2) + log (x  - 1) = log 6
log [(x-2)(x-1)] = log 6
log(x² - 3x + 2) = log 6

x² - 3x + 2 = 6
x² - 3x + 2 - 6 = 0
x² - 3x - 4 = 0
(x + 1)(x - 4) = 0

x + 1 = 0
x = -1 (tidak memenuhi)

x - 4 = 0
x = 4

HP = {4}

c)
log (2x - 1) - log (x - 3) = log 7
log [(2x - 1) / (x - 3)] = log 7

(2x - 1) / (x - 3) = 7
2x - 1 = 7(x - 3)
2x - 1 = 7x - 21
2x - 7x = -21 + 1
-5x = -20
x = 4

HP = {4}