Question

tolong dibantu ya Kak pake cara ya​

Answer 1

30.

[tex]r = \sqrt[2]{luas \div \pi} \\ = \sqrt[2]{2.826 \div 3.14} \\ = \sqrt[2]{900} \\ = 30m[/tex]

1.Diameter

2.Busur

3.Tembereng

4.Apotema

5.titik pusat

6.k=π×2r

=3, 14×2×15

=94, 2cm

7.

[tex]diameter= k \div \pi \ \\ \ = 88 \div \frac{22}{7} \\ = 28cm \\ \\ r = diameter \div 2 \\ = 28 \div 2 \\ = 14cm[/tex]

8.L=π×r²

=3, 14×20²

=3, 14×400

=1.256cm²

9.

[tex]d = k \div \pi \\ = 44 \div \frac{22}{7} \\ = 14cm \\ \\ r = 7 \\ \\ luas = \pi \times {r}^{2} \\ = \frac{22}{7} \times 49 \\ = 154 {cm}^{2} [/tex]

10.

[tex]l = \frac{1}{4} \times \pi \times {r}^{2} \\ = \frac{1}{4} \times \frac{22}{7} \times 196 \\ = \frac{1}{4} \times 616 \\ = 154 {cm}^{2} [/tex]

semoga membantu. kalau salah mohon di koreksi yaa