Dimensi Tiga
Kubus
r = 8 cm
BG diagonal sisi
BG = r√2 = 8√2 cm
P tengah GH
GP = PH = 1/2 GH = 8/2 = 4 cm
Panjang BP
= √(BG² + GP²)
= √((8√2)² + 4²)
= √(128 + 16)
= √144
= 12 cm
Jarak titik B ke P adalah 12 cm.
DImeNSI TigaKubuspanjang sisi= sdiagonal sisi = s√2
kubus ABCD EFGHs= 8panjang BG = s√2 = 8√2P tengah GH = PG = 1/2 s = 4
panjang BP = √(BG² - PG²)[tex]\sf BP = \sqrt{(8\sqrt2)^2 +4^2 } = \sqrt{128 + 16} = \sqrt{144}[/tex]BP = 12jarak B ke P = 12 cm
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Dimensi Tiga
Kubus
r = 8 cm
BG diagonal sisi
BG = r√2 = 8√2 cm
P tengah GH
GP = PH = 1/2 GH = 8/2 = 4 cm
Panjang BP
= √(BG² + GP²)
= √((8√2)² + 4²)
= √(128 + 16)
= √144
= 12 cm
Jarak titik B ke P adalah 12 cm.
Verified answer
DImeNSI Tiga
Kubus
panjang sisi= s
diagonal sisi = s√2
kubus ABCD EFGH
s= 8
panjang BG = s√2 = 8√2
P tengah GH = PG = 1/2 s = 4
panjang BP = √(BG² - PG²)
[tex]\sf BP = \sqrt{(8\sqrt2)^2 +4^2 } = \sqrt{128 + 16} = \sqrt{144}[/tex]
BP = 12
jarak B ke P = 12 cm