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Verified answer
Bab Bangun RuangMatematika SMP Kelas VIII
1] kubus
BE = diagonal sisi = s√2
BE = 5√2 cm
AG = diagonal ruang = s√3
AG = 5√3 cm
2] Balok
karena alas tidak diketahui, maka balok alas persegi
BE = √(BA² + AE²)
BE = √(4² + 3²)
BE = √(16 + 9)
BE = √25
BE = 5 cm
AG = √(AB² + BC² + CG²)
AG = √(4² + 4² + 3²)
AG = √(16 + 16 + 9)
AG = √41 cm
3] Balok
BE = √(BA² + AE²)
BE = √(4² + 6²)
BE = √(16 + 36)
BE = √52
BE = 2√13 cm
AG = √(AD² + DC² + CG²)
AG = √(8² + 4² + 6²)
AG = √(64 + 16 + 36)
AG = √116
AG = 2√29 cm