Question

tolong dibantu pliss​

Answer 1

Jawaban:

pldv

[tex]3x - 2y = - 4 \\ 2x + 3y = - 7 \\ [/tex]

persamaan (1) 3x - 2y = -4

persamaan (2) 2x + 3y = -7

[tex]3x - 2y = - 4 \\ 3x = 2y - 4 \\ x = \frac{2y - 4}{3} [/tex]

s substitusi ke dlm persamaan (2)

[tex]2x + 3y = - 7 \\ 2( \frac{2y - 4}{3}) + 3y = - 7 \\ 2(2y - 4) + 9y = - 21 \\ 4y - 8 + 9y = - 21 \\ 13y = - 21 + 8 \\ 13y = - 13 \\ y = - 1 [/tex]

substitusi nilai y = -1 kedlm persamaan (1)

[tex]x = \frac{2y - 4}{3} \\ x = \frac{2( - 1) - 4}{3} \\ x = \frac{ - 6}{3} \\ x = - 2[/tex]

HP (x , y) = { –2, –1 }

Answer 2

Penjelasan dengan langkah-langkah:

3x - 2y = -4 (×2)

2x + 3y = -7 (×3)

• 6x - 4y = -8
• 6x + 9y = -21 –

------------------------

-13y = 13

y = -1

3x - 2y = -4

3x - 2(-1) = -4

3x - (-2) = -4

3x = -4 + (-2)

3x = -6

x = -2

--------------------

= 2y - x

= 2(-1) - (-2)

= -2 + 2

= 0 (C)