Question

Tolong dibantu nomor 5 dan 6 terima kasih..

Answer 1

5. x-y+1=0
x²+y²-13=0

x-y+1=0
y=x+1

x²+(x+1)²-13=0
x²+(x²+2x+1)-13=0
2x²+2x-12=0
(2x-4)(x+3)=0
x1=2 atau x2=-3

y=x+1
y1=2+1=3
y2=-3+1=-2

6. x²-y²=0
2x+3y=4
x=(4-3y)/2
x=2-3y/2

(2-3/2y)²-y²=0
(4-6y+9y²/4)-y²=0
5y²/4 - 6y +4=0
5y²-24y+16=0
(5y-4)(y-4)=0
y1=4/5 atau y2=4

x1=2-3(4/5)/2 =2-6/5 =4/5
x2=2-3(4)/2 = 2-6 = -4

Answer 2

L h a k u i j a w a b a n e w es k o k t u l i s p o u r o n g h e