Jawab:
Turunan
y' = 0
fungsi turun y' < 0
fungsi naik y'> 0
Penjelasan dengan langkah-langkah:
y = 1/3 x³ - 5/2 x² + 6 x
x² - 5x + 6 = 0
(x - 2)(x - 3) =0
x = 2 atau x = 3
garis bilangan
...+....(2)..-...(3)...+...
titik balik min pada absis x = 3
y= 1/3 x³ - 5/2 x² + 6x
x= 3 --> y = 1/3 (27) - 5/2 (9) + 6(3)=4¹/₂
titk balik ( 3, 4¹/₂)
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Verified answer
Jawab:
Turunan
y' = 0
fungsi turun y' < 0
fungsi naik y'> 0
Penjelasan dengan langkah-langkah:
y = 1/3 x³ - 5/2 x² + 6 x
y' = 0
x² - 5x + 6 = 0
(x - 2)(x - 3) =0
x = 2 atau x = 3
garis bilangan
...+....(2)..-...(3)...+...
titik balik min pada absis x = 3
y= 1/3 x³ - 5/2 x² + 6x
x= 3 --> y = 1/3 (27) - 5/2 (9) + 6(3)=4¹/₂
titk balik ( 3, 4¹/₂)