Question

Tolong dibantu no 8 sampai 12 !!
dan pake caranya...

Answer 1

8. (4x⁻². y². z³) : (2x⁻¹.y . z²)³
= (4x⁻² y² z³); (8x⁻³ y³ z⁶)
= (4/8)(x⁻²/x⁻³) (y²/y³) (z³/z⁶)
= 1/2 (1/x⁵)(1/y)(1/z³)
= 1/(2x⁵yz³)

10. 
9 ³ˣ⁺² = 81²ˣ⁻⁵ 
9 ³ˣ⁺² = (9²)²ˣ⁻⁵
3x + 2 = 2(2x -5)
3x +2 = 4x - 10
(3-4)x = -10 - 2
-x = - 12
x = 12

11. 
2√75 (3√32)  : (√54) = 
= (2)(5)√3 .(3)(4)√2 : 3√6
= 10√3 . 12√2 : 3√6
= (120 √6); (3√6)
= 120/3
= 40

12. 
3√128 - 3√75 - √72 + √147 =
= 3(8√2) - 3(5√3)  - (6√2) + (7√3)
= (24 √2 -  6√2 - 15√3 + 7√3)
= (24-6)√ 2+ (-15+7)√3
= 18√2 - 8√3