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∑E + ∑IR = 0
(9 - 18) + I(3 + 0,5 + 2 + 0,5) = 0
-9 + 6I = 0
6I = 9
I = 9/6
I = 1,5 A
Jadi besar arus yang mengalir pada rangkaian adalah 1,5 A