Question

Tolong dibantu kakak

Answer 1

1/(x^2 . y) . 2x/(3y^2) . 5/(3x) .(4y^2)  .....saya ubah soalnya ya...^= pangkat
{1.(2/3).(5/3).4} .( x^-2 .y^-1. x^1 . y^-2 .x^-1 . y^-2)
{40} . (x⁻².x¹ . x⁻¹ . y⁻¹ .y⁻² .y⁻²)
= 40 . x⁻²⁺¹⁻¹ y⁻¹⁻²⁻²
= 40 x⁻² y⁻⁵
= 40/(x²y⁵)