Jawaban:
maaf kalau salah
semoga jadi jawaban tercerdas
mau tau jawaban nya lebi bagus cari zenius
Cosec B = -13/12 => sin B = -12/13
B di kuadran 4 maka Tan B <o, sin B<o
cos B >o
sin² B + cos²B = 1
(-12/13)² + cos²B = 1
144/169 + cos²B = 1
cos²B = 1 - 144/169
cos²B = 169-144/169
cos²B = 25/169
cosB = √25/169
cosB = 5/13
TanB = sin B / cos B
= -12/13 / 5/13
= -12/13 × 13/5
= -12/5 (B.)
[[ SN ]]
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Jawaban:
maaf kalau salah
semoga jadi jawaban tercerdas
mau tau jawaban nya lebi bagus cari zenius
Jawaban:
Cosec B = -13/12 => sin B = -12/13
B di kuadran 4 maka Tan B <o, sin B<o
cos B >o
sin² B + cos²B = 1
(-12/13)² + cos²B = 1
144/169 + cos²B = 1
cos²B = 1 - 144/169
cos²B = 169-144/169
cos²B = 25/169
cosB = √25/169
cosB = 5/13
TanB = sin B / cos B
= -12/13 / 5/13
= -12/13 × 13/5
= -12/5 (B.)
[[ SN ]]