Question

tolong dibantu + dijawab dengan caranya ​

Answer 1

Jawaban:

cos A

= -3/5 → sin A = √1 - (-3/5)²

= √1 - 9/25

= √16/2y = ± 4/5

Sin A = -4/5, karena A di kuadran lll (3)

tan B = -√21/2 → sec² B = tan² B + 1

1/cos²B = 21/4 + 1

1/cos²B = 25/4

cos²B = 4/25 → cos B = -2/5 karena B kuadran 2

sin B = √21/5

sin A cos B - Cos A Sin B = (-4/5)(-2/5)-(-3/5)(√21/5)

= 8/25 + 3√21/25 (E.)

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