Question

tolong dibantu dengan jalan nya ya kak ​

Answer 1

Integral

∫x^n dx = 1/(n + 1) x^(n + 1) + C

∫(4x⁶ - 4x³ + 16x² - 6x + 5) dx [1 -1]

= 4/7 x⁷ - 4/4 x⁴ + 16/3 x³ - 6/2 x² + 5x

= 4/7 x⁷ - x⁴ + 16/3 x³ - 3x² + 5x

= 4/7 (1⁷ - (-1)⁷) - (1⁴ - (-1)⁴) + 16/3 (1³ - (-1)³) - 3(1² - (-1)²) + 5(1 - (-1))

= 4/7 × 2 - 0 + 16/3 × 2 - 0 + 5 × 2

= 8/7 + 32/3 + 10

= 1 1/7 + 10 2/3 + 10

= 21 + (1/7 + 2/3)

= 21 + (3 + 14)/21

= 21 17/21