Question

Tolong dibantu dengan cara ya

Answer 1

< BCA + (3x-30°) = 180°

<BCA = 180° +30° - 3x

= 210° -3x

<CBA + (140°-x) = 180°

<CBA = 180° - 140° + x

= 40°+x

<BAC + <BCA + < CBA = 180°

70° + (210°-3x) + (40°+x) = 180°

320° -2x = 180°

-2x = 180°-320° = -140°

x = -140° ÷(-2) = 70°

<BCA = 210° - 3x

= 210° - 3(70°)

= 210° - 210° = 0°

yang bikin soal salah bikin