Phytagoras
[tex] {52}^{2} = ( {5x)}^{2} + ( {12x)}^{2} \\ 2.704 = 25 {x}^{2} + 144 {x}^{2} \\ 2.704 = 169 {x}^{2} \\ \frac{2.704}{169} = {x}^{2} \\ {x}^{2} = 16 \\ x = \sqrt{16} \\ x = 4 \\ \\ ketinggian \: pohon \\ 5x = 5(4) = 20 \: m[/tex]
52² = (5x)² + (12x)²
(52(52) = (5(5(x(x) + (12(12(x(x)
2.704 = 25x² + 144x²
2.704 = (25 + 144)x²
2.704 = 169x²
169x² = 2.704
x² = 2.704/169
x² = 16/1
x² = 16
x = √16
x = √4²
x = 4
MAKA :
t = (5 × 4) m
= 20 m
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Phytagoras
[tex] {52}^{2} = ( {5x)}^{2} + ( {12x)}^{2} \\ 2.704 = 25 {x}^{2} + 144 {x}^{2} \\ 2.704 = 169 {x}^{2} \\ \frac{2.704}{169} = {x}^{2} \\ {x}^{2} = 16 \\ x = \sqrt{16} \\ x = 4 \\ \\ ketinggian \: pohon \\ 5x = 5(4) = 20 \: m[/tex]
52² = (5x)² + (12x)²
(52(52) = (5(5(x(x) + (12(12(x(x)
2.704 = 25x² + 144x²
2.704 = (25 + 144)x²
2.704 = 169x²
169x² = 2.704
x² = 2.704/169
x² = 16/1
x² = 16
x = √16
x = √4²
x = 4
MAKA :
t = (5 × 4) m
= 20 m