Question

tolong dibantu abang abg suhu​

Answer 1

i^2 = -1

z = 1/i - 3i/(1 - i)

z = 1/i x i/i - 3i(1 + i)/(1 - i)(1 + i)

z = i/i^2 - (3i + 3i^2)/1 - i^2

z = i/-1 - (3i + (-3))/1 - (-1)

z = -i - (3i + (-3))/1 + 1

z = -i - (3i - 3)/2

z = -i - (-3 + 3i)/2

z = -i + 3/2 - 3/2i

z = -i - 3/2i + 3/2

z = (-2 - 3)/2i + 3/2

z = -5/2i + 3/2.

atau

z = 3/2 - 5/2i

Opsi D.