Tolong di jwb. dan tolong jgn jwb asal2an. yg tidak tqu tdk usah di jwb! ini bqgi yg tau aja!
5dregensleyerjawaban soal nomer 2 luas permukaa tampa tutup Lp = 5 x s² = 5 x 5² = 5 x 25 = 125 cm² jawaban soal nomer 3 sisi = KLMN , OPQR , KLPO , NMOR , LMQP , KNRO rusuk = KL , LM , MN , NK ,OP , PQ , QR , RO , OK , RN , PL , QM sudut = k , l , m , n , o , p , q , r bidang diagonal = KP , OL , NQ , RM , KM , NL , OQ , PR , LQ , PM, KN , OR digoal ruang = KQ , NP , OM , RL bidag diagonal = KLRQ .NMPO , MLOR , PQNK , jawaban soal nomer 4 volume balok = 31080 74 x 42 x l = 31 .080 3108 x l = 31.080 l = 31080/3108 l = 10 cm
luas permukaa tampa tutup
Lp = 5 x s²
= 5 x 5²
= 5 x 25
= 125 cm²
jawaban soal nomer 3
sisi = KLMN , OPQR , KLPO , NMOR , LMQP , KNRO
rusuk = KL , LM , MN , NK ,OP , PQ , QR , RO , OK , RN , PL , QM
sudut = k , l , m , n , o , p , q , r
bidang diagonal = KP , OL , NQ , RM , KM , NL , OQ , PR , LQ , PM, KN , OR
digoal ruang = KQ , NP , OM , RL
bidag diagonal = KLRQ .NMPO , MLOR , PQNK ,
jawaban soal nomer 4
volume balok = 31080
74 x 42 x l = 31 .080
3108 x l = 31.080
l = 31080/3108
l = 10 cm