Jawab:
Penjelasan dengan langkah-langkah:
Diketahui :
∠ADB = (2x + 15)°
∠BDC = (3x + 20)°
Ditanya : ∠ADB ...?
Penyelesaian :
∠ADB + ∠BDC = 180° (Sudut Berpelurus)
2x + 15° + 3x + 20° = 180°
5x + 35° = 180°
5x = 145°
x = 29°
∠ADB = 2x + 15°
= 2(29°) + 15°
= 58° + 15°
= 73°
TerimaKasih
Semoga Membantu :)
#BgGo
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Jawab:
Penjelasan dengan langkah-langkah:
Diketahui :
∠ADB = (2x + 15)°
∠BDC = (3x + 20)°
Ditanya : ∠ADB ...?
Penyelesaian :
∠ADB + ∠BDC = 180° (Sudut Berpelurus)
2x + 15° + 3x + 20° = 180°
5x + 35° = 180°
5x = 145°
x = 29°
∠ADB = 2x + 15°
= 2(29°) + 15°
= 58° + 15°
= 73°
TerimaKasih
Semoga Membantu :)
#BgGo