Jawaban:
2.
40°C = ? K
K = 40 + 273 = 313 K
40°C = 9/5 F + 32
F = 40 × 9/5 = 72 + 32 = 104°F
3.
6000 K = ... C
C = 6000 - 273 = 5.727°C
6.
40°C = ....°R
R = 4/5 C
= 40 × 4/5
= 32°R
11.
Q = m . c . ∆T
= 0,25 . 4200 (100-20)
= 84.000 J
Q = Banyak kalor
m = 250 g = 0,25 kg (jika satuannya J(Joule) gunakan kilogram)
c = kalor jenis
12.
30°C
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Jawaban:
2.
40°C = ? K
K = 40 + 273 = 313 K
40°C = 9/5 F + 32
F = 40 × 9/5 = 72 + 32 = 104°F
#B
3.
6000 K = ... C
C = 6000 - 273 = 5.727°C
6.
40°C = ....°R
R = 4/5 C
= 40 × 4/5
= 32°R
11.
Q = m . c . ∆T
= 0,25 . 4200 (100-20)
= 84.000 J
Q = Banyak kalor
m = 250 g = 0,25 kg (jika satuannya J(Joule) gunakan kilogram)
c = kalor jenis
12.
30°C