Soal Pertama :
8/12=DB/DB+3
8DB+24=12DB
24=4DB
6=DB
Jadi panjang AB adalah 6+3=9
Soal Kedua :
EF=(12×2)+(27×4) / 6
EF=22
11. AB/AC = BD/DE
3+x / 12 = x/8
8 (3+x) = 12x
24 + 8x = 12x
24 = 4x
6 = x = BD
AB = 3+x = 3+6 = 9 cm
12. FG/CG = BH/CH
x/4 = 15/6
15.4 = 6x
60 = 6x
10 = x = FG
EF = EG+FG
= 12 + 10
= 22 cm
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Soal Pertama :
8/12=DB/DB+3
8DB+24=12DB
24=4DB
6=DB
Jadi panjang AB adalah 6+3=9
Soal Kedua :
EF=(12×2)+(27×4) / 6
EF=22
11. AB/AC = BD/DE
3+x / 12 = x/8
8 (3+x) = 12x
24 + 8x = 12x
24 = 4x
6 = x = BD
AB = 3+x = 3+6 = 9 cm
12. FG/CG = BH/CH
x/4 = 15/6
15.4 = 6x
60 = 6x
10 = x = FG
EF = EG+FG
= 12 + 10
= 22 cm
Semoga membantu ;))