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i₁ = 4 A a₁ = 2×10⁻² m
i₂ = 6 A a₂ = 6×10⁻² m
B = __ ?
B = B₁ + B₂
= μ₀ i₁ / (2π a₁) + μ₀ i₂ / (2π a₂)
= μ₀ / 2π (i₁ / a₁ + i₂ / a₂)
= 4π×10⁻⁷ / 2π (4 / 2×10⁻² + 6 / 6×10⁻²)
= 2×10⁻⁷ (200 + 100)
= 2×10⁻⁷ · 300
= 6×10⁻⁵ T, masuk bidang kertas ← jawaban [C]