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b^2 - 4ac > 0
a = p
b = p + 2
c = -p + 4
b^2 - 4ac > 0
(p + 2)^2 - 4(p)(-p + 4) > 0
(p^2 + 4p + 4) - 4(-p^2 + 4p) > 0
(p^2 + 4p + 4) - (-4p^2 + 16p) > 0
p^2 + 4p^2 + 4p - 16p + 4 > 0
5p^2 - 12p + 4 > 0
(5p - 2)(p - 2) > 0
batas-batasnya : p = 2/5 dan p = 2
uji p di titik 0
(5(0) - 2)(0 - 2) > 0
(-2)(-2) > 0
4 > 0 (memenuhi)
Jadi,
p < 2/5 atau p > 2