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x = [-b ± √(b^2 - 4ac)] / 2a
= [-3 ± √(9 - 4.1.(-8))] / 2.1
= [-3 ± √41] / 2
x = (-3 - √41)/2 atau x = (-3 + √41)/2
2. 3x^2 - 11x + 6 = 0
=> (3x - 2)(x - 3) = 0
=> x = 2/3 atau x = 3